# Tall cardinal

## Contents

## Tall Cardinals

A cardinal $\kappa$ is **$\theta$-tall** iff there is an elementary embedding $j:V\to M$ into a transitive class $M$ with critical point $\kappa$ such that $j(\kappa)>\theta$ and $M^\kappa\subset M$. $\kappa$ is **tall** iff it is $\theta$-tall for every $\theta$; i.e. $j(\kappa)$ can be made arbitrarily large. Every strong cardinal is tall and every strongly compact cardinal is tall, but measurable cardinals are not necessarily tall. It is relatively consistent, however, that the least measurable cardinal is tall. Nevertheless, the existence of a tall cardinal is equiconsistent with the existence of a strong cardinal. Any tall cardinal $\kappa$ can be made indestructible by a variety of forcing notions,
including forcing that pumps up the value of $2^\kappa$ as high as desired. See [1].

## Strongly Tall Cardinals

A cardinal $\kappa$ is **strongly $\theta$-tall** iff there is some measure $U$ on a set $S$ witnessing $\kappa$'s $\theta$-tallness in the ultrapower of $V$ by $U$. More precisely, the ultrapower embedding $j:V\prec M$ has critical point $\kappa$, $M^\kappa\subset M$, and $j(\kappa)>\theta$. $\kappa$ is **strongly tall** iff it is strongly $\theta$-tall for every $\theta$. It is not known whether or not all strong cardinals are strongly tall, although every strongly $\theta$-compact cardinal is strongly $\theta$-tall. It is conjectured that strongly tall cardinals are equiconsistent with strong cardinals (and therefore with tall cardinals).

### Ultrapower Characterization

$\kappa$ is strongly $\theta$-tall iff $\kappa$ is uncountable and there is some set $S$ and an ultrafilter $U$ on $S$ with completeness $\kappa^+$ ($U$ is $\kappa$-complete but not $\kappa^+$-complete) such that, letting $j:V\prec M\cong Ult_U(V)$, $j(\kappa)>\theta$.

### Ultrafilter Characterization

$\kappa$ is strongly $\theta$-tall iff there is some set $S$, an ultrafilter $U$ on $S$, and a class $H$ of functions $H_\alpha:S\rightarrow\text{Ord}$ for each ordinal $\alpha$ such that:

- $\kappa$ is uncountable.
- $U$ has completeness $\kappa^+$.
- $H_0(x)=0$ for each $x\in S$.
- For each $\alpha$ and each $f:S\rightarrow\text{Ord}$, $\{x\in S:f(x)<H_\alpha(x)\}\in U$ iff there is some $\beta<\alpha$ such that $\{x\in S:f(x)=\beta\}\in U$. That is, $f(x)<H_\alpha(x)$ almost everywhere iff there is some $\beta<\alpha$ such that $f(x)=\beta$ almost everywhere.
- $\{x\in S:H_\theta(x)<\kappa\}\in U$. That is, $H_\theta(x)<\kappa$ almost everywhere.

## References

Main library